5(2w^2-1)-(10w^2-6)=-(w+2)

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Solution for 5(2w^2-1)-(10w^2-6)=-(w+2) equation: 



5(2w^2-1)-(10w^2-6)=-(w+2)

We move all terms to the left:

5(2w^2-1)-(10w^2-6)-(-(w+2))=0

We multiply parentheses

10w^2-(10w^2-6)-(-(w+2))-5=0

We get rid of parentheses

10w^2-10w^2-(-(w+2))+6-5=0



We calculate terms in parentheses: -(-(w+2)), so:

-(w+2)

We get rid of parentheses

-w-2

We add all the numbers together, and all the variables

-1w-2

Back to the equation:

-(-1w-2)



We add all the numbers together, and all the variables

-(-1w-2)+1=0

We get rid of parentheses

1w+2+1=0

We add all the numbers together, and all the variables

w+3=0

We move all terms containing w to the left, all other terms to the right

w=-3

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